A mass of an ideal gas undergoes a reversible
isothermal compression. Its molecules compared with
initial state, will have same
(A) Root mean square speed
(B) Mean momentum
(C) Mean kinetic energy
•A, B, C are correct
•A and C are correct
•B and C are correct
•Only A is correct
Answers
Given info: A mass of an ideal gas undergoes a reversible isothermal compression.
we have to find out the correct option (s), when its molecules compared initial state will have the same
(A) root mean square speed
(B) mean momentum
(C) Mean kinetic energy
- A, B , C are correct
- A and C are correct
- B and C are correct
- only A is correct.
solution : for an isothermal compression process,
change in temperature must be zero.
i.e., Temperature remains constant.
but we know, RMS = √{3RT/M} so, it will be same after compression.
mean momentum = mv
where v is mean velocity [ or average velocity ]
but we know, average velocity = √{8RT/πM}
so, mean momentum also will be same.
mean kinetic energy = 3/2 nRT , it is clear that after compression, it will be same.
Therefore correct option is (1) A, B and C are correct.
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