Question

A mass of M is suspended by a rope from a rigid support. It is pulled horizontally with a force F. If the rope makes an angle x with vertical in equilibrium, then the tension in the string is

Answer 1

this answe is correct.☺️

Answer 2

Answer:

The tension in the string is

$T=\frac{F}{sinx}$

Explanation:

Given that,

Mass suspended by rope from a rigid support is M

The force with which it is pulled horizontally is F

The angle it makes with vertical when it is pulled by the force is x

Therefore,resolving the tension along string and applied force along horizontal amd vertical directions we get

$T_{y}=Mg \\ = > Tcosx =Mg - - > (1)$

In the horizontal direction we have

$T_{x}=F \\ = > Tsinx = F - - > (2)$

From equation 1,we get tension as

$T=\frac{Mg}{cosx}$

From equation 2,we get tension as

$T=\frac{F}{sinx}$

Hence,the tension in the string is found to be

$T=\frac{F}{sinx}$

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