Question

A mass of M kg is suspended by weightless string . The horizontal force that is required to displace it until the string makes an angle of 45° with the initial vertical direction is ? [AIEEE 2006] ​

Answer 1

Answer:

Answer in a Picture:

Explaination:

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Answer 2

Explanation:- Here , the constant horizontal force required to take the body from position 1 to position 2 can be calculated by using work - energy theorem . Let us assume that body be taken slowly , so that its speed doesn't change then

• ∆K = 0 = Wᶠ + Wᵐᵍ + Wᵗᵉⁿᵗⁱᵒⁿ
• [Symbol have their usual meaning ]
• Wᶠ = FLsin45 ° = FL/ √2
• Wᵐᵍ = Mg (L- Lcos45°) , Wᵗᵉⁿˢⁱᵒⁿ = 0
• ∴ Wᶠ =- Wᵐᵍ
• FLsin45° = mg (L - L cos45°)
• Fsin45° = mg (1-cos45°)
• F× 1/√2 = mg (1-1/√2)

∴ F= mg (√2-1) Answer .

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