A mass of M kg is suspended to a weightless string.Find the horizontal force that is required to displace it until it makes an an angle 45 degree with initial vertical direction.
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Answer:
There are two components of T .
In vertical direction T sin 45° = T/√2 is balancing
weight = mg
So T/√2 = mg or T = √2 mg
Now in horizontal there is T cos 45° which will be balance by our force F
F = T cos45°= √2mg /√2 = mg
So
F = mg
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