a mass of steam at hundred degree celsius is to be passed into water of mass 200 gram at 20 degree Celsius to rise its temperature by 5 degrees celsius is
Answers
Answer:
11th
Physics
Thermal Properties of Matter
Calorimetry
Steam at 100 ∘ C is passed ...
PHYSICS
Steam at 100
∘
C is passed into 20 g of water acquires a temperature of 80
∘
C, the mass of water presents will be [Take specific heat of water 1 cal g
−1
c
−1
latent heat of steam = $$540 \cal \ g^{-1}$$]
MEDIUM
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ANSWER
Steam at 100
o
C, Water acquires= 20g, Temperature= 80
o
C
The mass of water presents will be
Take specific heat of water= 1cal/g/c
Latent heat of steam= 540g
−1
Water 80
o
C to 100
o
C, the heat=mst
=20×1×(100
o
−80
o
)
=20×20
=400cal
Temperature 100
o
C to 100
o
C heat consumption= mL
=20×540=10800 cal
Total= 10800+400=11200cal
⇒
400
11200
g=22.5
Mass of water will be= 22.5g .
Explanation:
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