Physics, asked by namaniya8917, 11 months ago

A mass on the end of a spring oscillates with an amplitude of 5 cm

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Answered by Anonymous

Answer:

Standard equation is x = A*cos (wt + B) A = Amplitude = 5 cm = 0.05 m w = angular frequency = 2*pi*f f = frequency = 1 Hz w = 2*pi*1 = 2*pi = 6.28 rad/sec Now given that when t = 0,

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