A mass tied to a string moves in a vertical circle with a uniform speed of 5 m/s as shown. At the point P the string breaks. The mass will reach a height above P of nearly (1) 1 m
(2) 0.5 m
(3) 1.27 m
(4) 1.25 m
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Explanation:Use 3rd equation of motion
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A mass tied to a string moves in a vertical circle with a uniform speed of 5 m/s as shown. At the point P the string breaks. The mass will reach a height above P of nearly
answer : option (4) 1.25 m
explanation : initial speed of particle , u = 5m/s
final speed of particle, v = 0
after breaking the string, acceleration acting on particle = acceleration due to gravity. i.e., a = g
using formula, v² = u² - 2gh
or, 0 = (5)² - 2 × 10 × h
or, h = 25/20 = 1.25 m
hence, the mass will reach a height above point P of nearby 1.25m
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