A mass when dropped vertically from the top of a smooth inclined plane reached the ground with a velocity of 50m/s . if it is allowed to move along the inclined plane ,what will be the horizontal component of the velocity on reaching the ground?angle of inclination of the plane is 30°
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sorry
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so here the answer
V= 50m/s cos 30 degree = under root 3/2
50 under root 3/2
then divide 50/2
25 under root 3 so here your answer
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