Question

A massive stone pillar 20 m high and of uniform crosssection
rests on a rigid base and supports a vertical load of
5.0 × 10⁵ N at its upper end. If the compressive stress in the
pillar is not to exceed 1.6 × 10⁶ N m⁻², what is the minimum
cross-sectional area of the pillar? Density of the stone
= 2.5 × 10³ kg m⁻³. (Take g = 10 N kg⁻¹)
(a) 0.15 m² (b) 0.25 m²
(c) 0.35 m² (d) 0.45 m²

Answer 1

Answer:the maximum stress will be at the bottom of the pillar

stress=

A

F

​

weight of the pillar is volume×density=length×Area×density=20×A×2.5×10

3

the weight at the bottom of the pillar is 5A×10

4

×g+5×10

5

compressive stress given is 16×10

6

therefore

16×10

5

=

A

5A×10

5

+5×10

5

​

A=0.45m

2

Explanation:

Answer 2

Answer:

.45m^2 is the answer. I think

Explanation:

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