a massless beam of length 5m is placed on two wedges A and B.
If three forces 3kN, 4kN and 5kN are applied on the beam ,then find normal reaction at A and B
Answers
Normal reaction at A is 22/5 kN and normal reaction at 38/5 kN
Explanation :
If the beam is supported and there is no movement then the moment of forces about any support should be equal to 0. Let us take for B
∑ Mb = 0
or the anticlockwise moment = clockwise moment
5 x Rₐ = 3 x 3 + 2 x 4 + 5 x 1 = 22
=> Rₐ = 22/5 KN
The total load is the sum of the reaction at A and reaction at B
Hence F = Rₐ + Rb
=> Rb = F - Rₐ
= (3 + 4 + 5) - 22/5
= 12 - 22/5
= (60-22)/5
=38/5 kN
Hence normal reaction at A is 22/5 kN and normal reaction at 38/5 kN
Answer:
Normal reaction at A is 22/5 kN and normal reaction at 38/5 kN
Explanation:
If the beam is supported and there is no movement then the moment of forces about any support should be equal to 0. Let us take for B
∑ Mb = 0
or the anticlockwise moment = clockwise moment
5 x Rₐ = 3 x 3 + 2 x 4 + 5 x 1 = 22
=> Rₐ = 22/5 KN
The total load is the sum of the reaction at A and reaction at B
Hence F = Rₐ + Rb
=> Rb = F - Rₐ
= (3 + 4 + 5) - 22/5
= 12 - 22/5
= (60-22)/5
=38/5 kN
Hence normal reaction at A is 22/5 kN and normal reaction at 38/5 kN