Question

A massless conical flask filled with a liquid is kept
on a table in vacuum. The force exerted by the
liquid on the base of the flask is W,. The force
exerted by the flask on the table is W.
2
(A) W = W₂
(B) W, > W
(C) W, <W,
(D) The force exerted by the liquid on the walls of
the flask is (W.-W..
​

Answer 1

Answer:

So correct relation between the forces are

$W_1 < W_2$

$N_{wall} = W_2 - W_1$

Explanation:

As we know that the liquid is filled in the conical flask so here if we draw the FBD of liquid then by force balance on that liquid we will have

$N + N_{wall} = W$

so we have

$W_1 = W - N_{wall}$

here we know that

W_1 = force due to base of the flask on the liquid

$N_{wall}$ = Force due to side wall of the liquid

Now if we draw the FBD of the container then we will have

$W_2 = W$

So we can see here that the force due to table will be more than the force due to base of the flask

so we will have

$W_1 < W_2$

also we know that

force due to side wall

$N_{wall} = W_2 - W_1$

#Learn

Topic : Force due to liquid

https://brainly.n/question/14151196

Answer 2

Answer:

B,D

Explanation:

For equilibrium of liquid, side walls of flask exert

a force in downward direction on liquid due to which net force

on base by liquid increase hence W1 > W2 and by Newton's

third law option (D) is also correct.