Question

a massless spring of spring constant 100n/m in its unstretched position is hanged from the ceiling . A mass of 2 kg is attached and let go . find the maximum elongation in the spring

Answer 1

Answer:

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Answer 2

Answer:

A massless spring of spring constant 100 N/m in its upstretched position is hung from the ceiling. A mass of 2 kg is attached and let go, the elongation in the spring is $0.196m$

Explanation:

• The restoring force on a spring of spring constant (K) when elongated to a distance (x) is given as $F=-Kx$

• Due to the mass (m) attached to the spring the gravitational force on the mass is  $F=mg$

        where $g=9.8m/s^{2}$(acceleration due to gravity)

• at maximum elongation both the forces are balanced, that is $-Kx=mg$

From the question, we have

spring constant $K=100N/m$

mass attached $m=2kg$

maximum elongation of the spring $x=mg/K$

put the given values

⇒ $x=\frac{2*9.8}{100}=0.196m$