A match box dimension is 4 cm*2.5 cm*1.5 cm.what will be the volume of a packet containing 6 such match boxes ?how many such packets can be placed in a cardboard box whose size is 60 cm*30 cm*24 cm?
Answers
Step-by-step explanation:
Volume of 1 match box = l× b × h
= 4 × 2.5 × 1.5
= 15 cm^3
Volume of a packet containing 6 such match boxes = 6 × volume of 1 match box
= 6 × 15
= 90 cm^3
Volume of cardboard = l × b × h
= 60 × 30 × 24
= 43200 cm^3
No. of packets placed in a cardboard = volume of cardboard box / volume of 1 packet
= 43200 / 90
= 480 packets
Answer:
480 boxes
Step-by-step explanation:
volume of one match box =l*b*h
=(4*2.5*1.5)cm ²
=15 cm²
A box contains 6 packet of match box
so,
volume of box= 6* colume of matchbox
=(6*15)cm²
=90 cm ²
volume of cardboard=l*b*h
=(60*30*24)cm²
=43200 cm²
Number of matchbox =volume of cardboard /volume of box
= 43200/90
=480