Question

A match box measures 4 cm by 2.5 cm by 1.5 cm. What will be the volume of packet containing 12 such match boxes

Answer 1

Hey, here is your answer

length = 4cm , breadth = 2.5 cm , height = 1.5 cm

volume = length ×breadth ×height
=( 4×2.5×1.5 )cm^3
=15 cm^3

now,
volume of packet containing 12 such boxes = (12 × 15) cm^3
= 180 cm^3

hope it helps you ..
plz make it brainlist answer...

Answer 2

Answer:

2880

Step-by-step explanation:

Answer & Solution:

1 Match Box,

Length = 4 cm

Breadth = 2.5 cm

Height = 1.5 cm

Volume = l*b*h

= [4*2.5*1.5] cm³

= 15 cm³

Volume of 12 such match boxes = [15*12] cm³

= 180 cm³

Cardboard box,

Length = 60 cm

Breadth = 30 cm

Height = 24 cm

Volume = l*b*h

= [60*30*24] cm³

= 43200 cm³

∴ No. of boxes in 43200 cm³ box = [43200/15]

= 2880

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