A match boxes has dimensions 6 cm × 4 cm × 2 cm what will be the volume of a packet containing 15 such matchboxes .
Answers
Answer:
volume=l*b*h
= 6*4*2
volume of one box=48
no of boxes
=15
total volume = no of boxes*volume of one box
=15*48
= 720
Answer:
Length of a match box = 6cm.
Breadth of a match box = 4cm.
Height of a match box = 2cm
Volume of one match box = l x b x h
= 6 x 4 x 2
= 48 sq.cm
No, of match boxes = 15
Therefore, Volume of packet of 15 match boxes = 48
x 15
--------------
240
+ 480
---------------
720
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