Question

a matchbox has dimensions 6 cm *4cm*2cm what will be the volume of a packet containing 15 such matchbox​

Answer 1

Answer:

volume of 15 such matchboxes will be = 720cm3

Step-by-step explanation:

Answer 2

Answer:

$volume \: of \: 1 \: \: matchbox = 6cm \times 4cm \times 2cm = {48cm}^{3}$

$volume \: of \: 15 \: such \: machbox = 15 \times {48cm}^{3} = 720 {cm}^{3}$

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