Question

A matchbox is 6 cm long , 3.5 cm broad and
1.5 cm in height. Its outer sides are to be
covered exactly with craft paper. How much
paper
will be required to do so?​

Answer 1

Given :

• Dimensions of a match box :-

• Length of a match box = 6 cm
• Breadth of a match box = 3.5 cm
• Height of a match box = 1.5 cm

To find :

• Amount of paper required to cover the match box

Knowledge required :-

• Formula of of total surface area of cuboid :-

→ TSA of cuboid = 2(lb + bh + hl)

where,

• l is the length of the cuboid
• b is the breadth of the cuboid
• h is the height of the cuboid

Solution :

⠀⠀⠀⇒ TSA = 2(6 × 3.5 + 3.5 × 1.5 + 1.5 × 6)

⠀⠀⠀⇒ TSA = 2(21 + 5.25 + 9)

⠀⠀⠀⇒ TSA = 2(35.25)

⠀⠀⠀⇒ TSA = 70.5

★ Therefore, the area of paper required to cover the match box = 70.5 cm²

━━━━━━━━━━━━━━━

Some related formulae :-

• Area of square = side × side
• Perimeter of square = 4 × side
• Diagonal of square = √2a
• Perimeter of reactangle = 2(l + b)
• Diagonal of rectangle = √l² + √b²
• Volume of cuboid =  length × breadth × height
• Perimeter of cuboid = 4 (length + breadth + height)
• Total surface area of cube = 6 × side²
• Volume of cube = side³
• Perimeter of cube = 12 × side