A matchbox measures 4cm×2.5cm×1.5cm. What is the volume of a packet containing 12 such matchboxes?
Answers
Step-by-step explanation:
VOLUME:
The space occupied by an object solid body
is called the volume of the particular object solid body volume is always
measured in cubic unit.
Given:
Dimension of matchbox =4cm×2.5cm×1.5cm
l=4cm,b=2.5cm & h=1.5cm
Volume of cuboid =(l×b×h)
Volume of one matchbox = Volume of cuboid
Volume of one matchbox =4×2.5×1.5=15cm
3
Volume of a packet containing 12 such boxes = 12× volume of one match box
(12×15)cm
3
=180cm
3
Hence, the volume of a packet containing 12
such boxes=180cm
3
➢ Given:
- length of the matchbox, l ➝ 4 cm
- breadth of the matchbox, b ➝ 2.5cm
- height of the matchbox, h ➝ 1.5 cm
➢ To Find:
- Volume of 12 matchboxes
➢ Formula Required:
- Volume of a Cuboid ➛ l × b × h
➢ Solution:
∴ Volume of one matchbox ➠ l × b × h
➦ Volume of one matchbox ➠ 4 × 2.5 × 1.5 cm³
➦ Volume of one matchbox ➠ 4 × 3.75 cm³
➦ Volume of one matchbox ➠ 15.00 cm³
➦ Volume of one matchbox ➠ 15 cm³
∴ Volume of the matchbox containing 12 such boxes ➙ 15 × 12 cm³
➦Volume of the matchbox containing 12 such boxes ➙ 180 cm³
Hence, the required volume of 12 matchboxes is 180 cm³
➢ More Formula for volume:
- Volume of Cuboid ➠ l × b × h
- Volume of Cube ➠ a³
- Volume of Sphere ➠ 4/3πr³
- Volume of Hemisphere ➠ 2/3πr³
- Volume of Cone ➠ 1/3πr²h
- Volume of Cyclinder ➠ πr²h