Question

A Matchbox Measures $4\: cm \times 2.5\: cm \times 1.5\: cm$. What will be the Volume of a Packet containing 12 such Boxes?

Answer 1

Step-by-step explanation:

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Answer 2

Solution :-

$\bold {Given} \begin{cases}\bold {Length\: of\: the\: Matchbox} & = 4\: cm} \\\bold {Breadth} & = 2.5\: cm\\\bold {Height} & = 1.5\: cm\end{cases}$

To Find:- The Volume of a Packet containing 12 Such Boxes.

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Using the Formula, $\boxed {\bold {Volume\: of\: a \: Cuboid = Length \times Breadth \times Height}}$ ,

Volume of one Match Box, V = $4 \times 2.5 \times 1.5\: cm^3$

$\implies 10 \times 1.5 = \bold {15\: cm^3}$

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Number of Boxes = 12

Hence. Volume of 12 Match Boxes ⇒ $15 \times 12\: cm^3 = \underline {\bold {180\: cm^3}}$

∴ Volume of a Packet containing 12 Match Boxes = $\bold {180\: cm^3}$