Question

A material has a poison ratio 0.3 If a uniform rod of it surfaces longitude strain 4.5*10^(-3) calculate the percentage change in its volume..✌❤​

Answer 1

$\huge\frak{\underline{\underline{\red{Your\:Answer:}}}}$

$\implies\sf$ $\large{\boxed{\boxed{0.18}}}$

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Explanation:

Given:

Poisson's ratio $0.3$

longitudinal strain $4.5×10^{-3}$

As σ = $\frac{-ΔR/R}{ΔL/L}$

∴$\frac{ΔR}{R}$ = $\frac{-σΔL}{L}$

= $0.3*4.5*10^{-3}$ $\implies\sf$ $1.35 * 10^{-3}$

$V = πR^{2}l$

∴$\frac{ΔV}{V}*100=(\frac{2ΔR}{R}+\frac{Δl}{l})*100$

$\implies\sf$ $[2*(1.35 *10^{-3})+4.3*10^{-3}*100]$

$\implies\sf$$1.8*10^{-3}*100$

$\implies\sf$0.18%

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Answer 2

Answer:

If a uniform of it suffers longitudinal strain 4.5×10-3, calculate the percentage change in its volume. =(1.8×10-3)×100=0.18%.....

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