Question

A material has poisson's ratio 0.50.If a uniform rod of it suffers a longitudinal strain of 2×10^-3,what is the percentage change in volume ?​

Answer 1

  dVV=(1+2σ)dLL             dVV=2×2×10−3=4×10−3 [∵σ=0.5=12] Percentage change in volume =4×10−1=0.4