Question

A material has poisson's ratio of 0.5. If a uniform rod suffers a longitudinal strain of 2 x 10 −3 the percentage increase in its volume is :

Answer 1

Answer:

The volume change of a material due to the strain is related to the poisson's ration by the relation:

ΔV/V=(1−2×σ)ΔL/L where, σ is the poisson's ratio of the material.

In this case the term in the bracket of RHS is zero since σ is 0.5. So percentage volume change is 0%.

Explanation:

answer is 0....

Answer 2

Answer:

We know

(dv / v) = (1 – 2σ) (dL / L)

Given : σ = 0.5

Strain = (dL / L) = (2 × 10–3)

∴ (dv / v) = {1 – (2 × 0.5)} (dL / L)

(dv / v) = 0

Explanation:

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