A material particle with a rest mass m₀ is moving with speed
of light c. The de-Broglie wavelength associated is given
by
(a) h/m₀c
(b) m₀c/h (c) zero (d) [infinity]
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Answer:
Dea Student,
Speed of the electron, v=0.5c (c is speed of light which is 3×108 ms−1)v=0.5× 3×108 ms−1 =1.5×108 ms−1
According to De Broglie's equation
λ (wavelength)=h (Planck's constant)p (momentum)=hmv
λ=hmv=6.626×10−34J s9.11×10−31Kg ×1.5×108ms−1=4.848×10−12 m
Regards
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