Question

A mathbox measures 4 cm * 2.5 cm*1.5 cm.What will be the volume of a packet containing 12 dozen such boxes

Answer 1

match box is a type of cubiod
the volume of 1 match box =lbh
4cm×2.5× 1.5= 15cm^3
volume of 12×12 boxes
144 × 15m^3= 2160cm^3

Answer 2

$volume \: of \: matchbox=(4 \times 2.5 \times 1.5) cm^{3} \\ = (10.0 \times 1.5) {cm}^{3} \\ = 15 {cm}^{3}$

Now,

$required \: volume=144 \times volume \: of \: one \: matchbox \\ = (12 \times 12 \times 15) {cm}^{3} \\ = 2160 {cm}^{3}$

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