Question

A matrix ARR[-4....6,3...8] is stored in the memory with each element
requiring 4 bytes of storage. If the base address is 1430. find the address ofARR[3][6] when the matrix is stored in Row Major Wise.​

Answer 1

Answer:

Here is my answer

Explanation:

8] is stored in the memory with each element requiring 4 bytes of storage. If the base address is 1430, find the address of ARR[3][6] when the matrix is stored in Row Major Wise. Number of columns, C = 8 – 3 + 1 = 6. ⇒ Address of ARR[3][6] = 1610.

Answer 2

Given:

ARR[-4....6 , 3....8]

W = 4

B = 1430

I = 3

J = 6

Lr = -4

Lc = 3

To find:

The address of ARR[3][6] when the matrix is stored in Row Major Wise.​

Solution:

No. of columns (C) = 8 - 3 + 1 = 6

Address of [I , J]th element in row major = B + W[C(I - Lr) + (J - Lc)]

ARR[3][6] = 1430 + 4[6(3 - (-4) + (6 - 3)]

= 1430 + 4[6(3 + 4) + 3)

= 1430 + 4[6(7) + 3]

= 1430 + 4[42 + 3]

= 1430 + 4[45]

= 1430 + 180

= 1610

So, the address of ARR[3][6] is 1610 when the matrix is stored in Row Major Wise.