A mauble statue is being carved
by a sculptor. In the first week 35%
is cut away, in the second week 20%
of the remainder is cut away and
in the third week 25% 4 the
Memainder is cut away and polished
to produce the final statue!
The weight of the final statue is
48.75 lbs. What was the weight of
the original piece of marble ?
Answers
Answered by
1
Let original weight be x
In first week , 35% is cut away
Remaining weight = x-35% of x = 0.65x
Statue cut in second week =
20/100 * 0.65x = 0.13x
Remaining weight after second week = 0.65x-0.13x = 0.52x
Statue cut in third week = 25/100 *0.52x = 0.13x
Remaining weight after third week = 0.52x-0.13x = 0.39x
So, 0.39x = 48.75
x = 125lbs
Step-by-step explanation:
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