Math, asked by rohitsharma4515, 10 months ago

A mauble statue is being carved
by a sculptor. In the first week 35%
is cut away, in the second week 20%
of the remainder is cut away and
in the third week 25% 4 the
Memainder is cut away and polished
to produce the final statue!
The weight of the final statue is
48.75 lbs. What was the weight of
the original piece of marble ?​

Answers

Answered by Anonymous
1

Let original weight be x

In first week , 35% is cut away

Remaining weight = x-35% of x = 0.65x

Statue cut in second week =

20/100 * 0.65x = 0.13x

Remaining weight after second week = 0.65x-0.13x = 0.52x

Statue cut in third week = 25/100 *0.52x = 0.13x

Remaining weight after third week = 0.52x-0.13x = 0.39x

So, 0.39x = 48.75

x = 125lbs

Step-by-step explanation:

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