Question

a maximum horizontal range of the projectile is 40m the maximum height is ??​

Answer 1

Answer:

maximum height = 10 m

Step-by-step explanation:

As we know that for maximum height Φ must be 45°

Horizontal Range Formula :-

R = 2usinΦ.ucosΦ/g.......(1)

Maximum Height Formula :-

Hmax = u²sin²Φ/2g........(2)

now eq.(2)/ eq.(1)

Hmax/40 = u²sin²Φ*g/2g*2u²sinΦ.cosΦ

Hmax/40 = u²sin²Φ*g/2g*2u²sinΦ.cosΦHmax/ 40 = sinΦ/4 cos Φ

Hmax/40 = u²sin²Φ*g/2g*2u²sinΦ.cosΦHmax/ 40 = sinΦ/4 cos ΦHmax = tan Φ*40/4

Hmax/40 = u²sin²Φ*g/2g*2u²sinΦ.cosΦHmax/ 40 = sinΦ/4 cos ΦHmax = tan Φ*40/4Hmax = tan 45°*10

Hmax/40 = u²sin²Φ*g/2g*2u²sinΦ.cosΦHmax/ 40 = sinΦ/4 cos ΦHmax = tan Φ*40/4Hmax = tan 45°*10Hmax = 10 m

Thus maximum height is 10 m