Question

A maximum of 500 tourists went on a road trip. 8 buses were filled and the
remaining 9 tourists went in a car. Express this in an algebraic equation


dent understood it

Answer 1

The algebraic equation is 8x+9=500.

Given: A maximum of 500 tourists went on a road trip. 8 buses were filled and their remaining 9 tourists went in a car.

To find: We have to express it in an algebraic equation.

Solution:

Let the number of people going on each bus be x.

8 buses were filled.

So, we can say a total of 8x people travelled in the bus. A maximum of 500 tourists goes

on a road trip.

So, the total number of tourists is 500.

Among the tourists remaining 9 tourists went in a car.

So, the algebraic equation is-

$8x + 9 = 500$

Answer 2

A maximum of 500 tourists went on a road trip. 8 buses were filled and the remaining 9 tourists went in a car then Algebraic inequality will be 8x + 9 ≤ 500 where x in number of tourist in each bus.

Algebraic Equation will be 8x + 9  = 500 if exactly 500 tourist instead of maximum 500 is given

Step 1:

A maximum of 500 tourists went on a road trip.

Hence Number of tourist less than or Equal to 500

Number of Tourist ≤ 500

Step 2:

8 buses were filled

Assume number of tourist in each bus = x

Hence Tourist in 8 buses = 8x

Step 3:

Tourist Went in Car = 9

Step 4:

Total Tourist

8x + 9

Step 5:

Number of Tourist ≤ 500 hence

8x + 9 ≤ 500

Algebraic Inequality formed in 8x + 9 ≤ 500

To Form Algebraic equation , number of tourist given must be exactly 500 instead of maximum 500

Then Algebraic Equation will be 8x + 9  = 500

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