Economy, asked by tejasacharya30, 3 months ago

A measure of dispersion is a good supplement to the central value in
understanding a frequency distribution. Comment.​

Answers

Answered by s15846cnistha007261
0

Answer:

Answer−

\begin{gathered}\begin{gathered}\begin{gathered}\bf \: Let - \green{\begin{cases} &\tt{denominator \: = x} \\ &\sf{numerator \: = \: x - 4} \end{cases}}\end{gathered}\end{gathered}\end{gathered}

Let−{

denominator=x

numerator=x−4

So,

\begin{gathered}\begin{gathered}\bf \:fraction - \purple{\begin{cases} &\bf{\dfrac{x - 4}{x} } \end{cases}}\end{gathered}\end{gathered}

fraction−{

x

x−4

\large \underline{\tt \: \red{ According \: to \: statement }}

Accordingtostatement

if 1 is subtracted from numerator and 3 is added to the denominator, fraction becomes 1/5.

Now,

\rm :\implies\:Numerator = x - 4 - 1 = x - 5:⟹Numerator=x−4−1=x−5

\rm :\implies\:Denominator = x + 3:⟹Denominator=x+3

So,

\begin{gathered}\begin{gathered}\bf \:fraction - \pink{\begin{cases} &\bf{\dfrac{x - 5}{x + 3} } \end{cases}}\end{gathered}\end{gathered}

fraction−{

x+3

x−5

\large \underline{\tt \: \blue{ According \: to \: statement }}

Accordingtostatement

\rm :\implies\:\dfrac{x - 5}{x + 3} = \dfrac{1}{5}:⟹

x+3

x−5

=

5

1

\rm :\implies\:5x - 25 = x + 3:⟹5x−25=x+3

\rm :\implies\:5x - x = 25 + 3:⟹5x−x=25+3

\rm :\implies\:4x = 28:⟹4x=28

\rm :\implies\: \boxed{ \green{ \bf \:x = 7 }}:⟹

x=7

\begin{gathered}\begin{gathered}\bf So,\:fraction - \green{\begin{cases} &\tt{\dfrac{x - 4}{x} =\dfrac{7 - 4}{7} = \dfrac{3}{7} } \end{cases}}\end{gathered}\end{gathered}

So,fraction−{

x

x−4

=

7

7−4

=

7

3

Explanation:

Answer−

\begin{gathered}\begin{gathered}\begin{gathered}\bf \: Let - \green{\begin{cases} &\tt{denominator \: = x} \\ &\sf{numerator \: = \: x - 4} \end{cases}}\end{gathered}\end{gathered}\end{gathered}

Let−{

denominator=x

numerator=x−4

So,

\begin{gathered}\begin{gathered}\bf \:fraction - \purple{\begin{cases} &\bf{\dfrac{x - 4}{x} } \end{cases}}\end{gathered}\end{gathered}

fraction−{

x

x−4

\large \underline{\tt \: \red{ According \: to \: statement }}

Accordingtostatement

if 1 is subtracted from numerator and 3 is added to the denominator, fraction becomes 1/5.

Now,

Numerator

fraction−{

x+3

x−5

x+3

x−5

x

x−4

=

7

7−4

=

7

3

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