A measuring barometer reads 72 CM when 3 cm3 of air is added into it. The length of air in the tube is 28 CM and the barometer reads 52 CM. Find area of cross section of tube
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Initial volume of air V1=3cm3 at a pressure P1 = atmospheric pressure =75cm of mercury.
The level of mercury falls to 65 cm because the air in the tube exerts pressure on it. Therefore, pressure of air inside the tube, P2=75-65=10cm of Hg.
Given, length of air column =15cm . If Acm2 is the area of cross section of the tube, then volume of the trapped airV2=15×A cm3.
By Boyle,s law. P1V1=P2V2
75×3=10×(15×A)
∴A=75×310×15=1.5cm2.
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