A measuring cylinder contains water to a level of 22 ml . The water level rises to 30 ml when a piece of copper is completely immersed in it . Find the value of copper piece in (a) cm³ and (b) m³ .
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a- 8mL
b-8×10^-6m^3
Explanation:
[a] Volume of copper piece V =V2 -V1
=30mL - 22mL = 8mL
since 1mL= 1cm^3, V =8cm^3
[b] Since 1cm^3=10^-6m^3
Volume of copper piece = 8×10^-6 m^3
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