Question

A measuring cylinder contains water upto the 46ml mark.When a stone is immersed in it,the water level rises upto 74ml.If the mass of the stone is 45g,find the density of stone. EMERGENCY!!!!!!!!!!!!111

Answer 1

Answer: Density is 1.60714285714 $gcm^{-3}$ .

Explanation:  Amount of water in the measuring cylinder = 46 ml

                        Level of water after the immersion of a stone = 74 ml

                       Mass = 45 g

                        Volume = (74 - 46) ml= 28 ml = 28 $cm^{3}$

Hence, density = Mass/ Volume = (45 / 28) $gcm^{-3}$

                                                        = 1.60 $gcm^{-3}$ (approx)

                                                        = 1.60714285714 $gcm^{-3}$

Answer 2

Answer:

$Density is 1.60714285714 gcm^{-3}gcm−3$.

Explanation: Amount of water in the measuring cylinder = 46 ml

Level of water after the immersion of a stone=74 ml

Mass = 45 g

Volume =$(74-46)ml=28ml=28cm^{3}cm 3$

Hence, density = Mass/ Volume = $(45 /28)gcm^{-3}gcm −3$

$=1.60gcm^{-3gcm −3 (approx)$

$=1.60714285714 gcm^{-3}gcm −3$