Question

A measuring cylinder has 5 marks between 10 mL to 20 mL. What is it least count?​

Answer 1

20 mL $-$ 10 mL $=$ 10 mL,

Let 'x' is the least count.

Therfore,

5 $×$ x $=$ 10

x $=$ 10/5 $=$ 2

Each mark is of 2 mL value.

Answer 2

Answer:

20 mL – 10 mL = 10 mL

∵ 5 × 2 = 10 Each mark is of 2 mL