Question

A mechanic can open a nut by applying a force of 60 N while using a lever handle of 25 cm. How long handle is required if he wants to open the nut by applying a force of 20 N?

Answer 1

force =60N

displacement=0.2

mass=60/0.25 kg=240kg

240d=20

=>d=1/12

=>d=0.08

length of handle =80

Answer 2

Answer:

$length \: of \: handle \: if \: h \: ia \: able \: to \: open \: it \: by \: applying \: a \: force \: of \: 60n \: is \: 1m \\ let \: forces = f1 \: and \: f2 \: length \: = l1 \: and \: l2 \\ 150 \times 0.4 = 60 \times 12 \\ 12 = 1m \\ give \: me \: some \: multiple \: thanks \:$