Question

a mechanic opens a nut by applying a force of 180 N by using a wrench of length 25 cm. If the mechanic wants to open it by a force of 50N, what should be the length of wrench​

Answer 1

In the 1st case, the force applied,

F = 120 N and the magnitude of the perpendicular distance (called radius vector),

r=40cm=

40

100

 

m

Torque (τ)=120N×

40

100

 

=48Nm.

In the 2nd case, applied force F = 40 N and the length of the radius vector is to be found.

r=?

τ=F×r is the same in both the cases.

Hence,

48=40×r

∴r=1.2m. Hence, to apply a force of 40 N for the same torque, the mechanic should use a spanner of length 1.2 m.

Answer 2

Answer:

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