Question

A mechanical strikes a nail with hammer moving with the velocity of 20m/s. The hammer comes to rest in 0.002s after striking the nail . Calculate the acceleration of nail

Answer 1

Answer :-

-10000m/s^2

Explanation :-

Given :

Initial velocity of the moving hammer,u = 20m/s

Final velocity of the moving hammer,v = 0m/s

Time taken,t = 0.002s

To Find :

Acceleration,a = ?

Solution :

According to first law of motion:

$\sf{}v=u+at$

So,

$\sf{} \implies 0 =20 m/s+0.002s \times a$

$\sf{} \implies -20m/s= 0.002s \times a$

$\sf{} \implies -\dfrac{20m/s}{0.002s}= a$

$\sf{} \therefore a= -10000m/s^2$

Therefore,acceleration is equal to -10000m/s^2

Know more :

$\sf{} Second\ equation\ of\ motion: s=ut+\dfrac{1}{2}at^2$

$\sf{}Third\ equation\ of\ motion: v^2=u^2+2as$

Answer 2

Answer:

• Initial Velocity ( u ) = 20 m/s
• Final Velocity ( v ) = 0 m/s [As Hammer will come to the rest after striking]
• Time Taken ( t ) = 0.002 s

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf Acceleration=\dfrac{Final\: Velocity-Inital\: Velocity}{Time}\\\\\\:\implies\sf Acc^{n} = \dfrac{0 - 20}{0.002}\\\\\\:\implies\sf Acc^{n} = \dfrac{ - 20}{0.002}\\\\\\:\implies\sf Acc^{n} = \dfrac{ - 20 \times 1000}{2}\\\\\\:\implies\sf Acc^{n} = - 10 \times 1000\\\\\\:\implies\underline{\boxed{\sf Acc^{n} = - 10000\:m\:s^{-2}}}$

⠀

$\therefore\:\underline{\textsf{Acceleration of hammer would be \textbf{- 10000 m s ^{\text{-2}} }}}.$