A mechine gun fires a bullet of mass 40 g each with speed of 1200 m/s .the person can hold the gun with maximum force of 144 newton. What is the maximum number of bullet can be fired per second
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Mass of each bullet = 40 g = .040 kg
Velocity of each bullet = 1200 m/s
Let 'n' be the number of bullets fired per second. Then, change in momentum of the bullets coming out per second is,
= force on the man
=> n (0.040)(1200) = 144
=> n =3
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