A medical camp was held in a school to impart health education and the
importance of exercise to children. During this camp, a mdical check of 35
students was done and their weights were recorded as follows:
Weight (in kg)
below 40
below 42
below 44
below 46
below 48
below 50
helow 52
No. of Students
3
5
9
14
28
31
35
Answers
Given :
Weight (in kg) No. of Students
below 40 3
below 42 5
below 44 9
below 46 14
below 48 28
below 50 31
below 52 35
To Find :
a). Modal class of the given data
b). Median class of the given data
c). Mean of the given data
d). The sum of the lower limit of the median class and the lower limit of the modal class
Solution:
Weight f cf Mid d=(mid - 45)/2 df
38 - 40 3 3 39 -3 -9
40 - 42 2 5 41 -2 -4
42 - 44 4 9 43 -1 -4
44 - 46 5 14 45 0 0
46 - 48 14 28 47 1 14
48 - 50 3 31 49 2 6
50 - 52 4 35 51 3 12
15
35/2 = 17.5
Hence median class = 46 - 48
Median class of the given data = 46 - 48
Highest frequency = 14
Modal class = 46 - 48
Mean of the given data
= 45 + 2 * 15/35
= 45 + 0.857
= 45.857
Sum of lower limit of the median class and the lower limit of the modal class
= 46 + 46
= 92
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