a medical lab has a 16g of sample of radioactive isotopes. after 6 hours it was found that 12g of a sample have decayed . the half life of the isotope is:
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let's use one of the standard half-life equations
N/No = e^(-0.693 T/K)
N = 16 - 12 = 4 g
No = 16 g
T = 6 hr
solve for K (half-life)
4/16 = e^(-0.693 * 6/K)
lake natural log of both sides (Ln)
-1.386 = -0.693 * 6 / K
K = 3 hr
N/No = e^(-0.693 T/K)
N = 16 - 12 = 4 g
No = 16 g
T = 6 hr
solve for K (half-life)
4/16 = e^(-0.693 * 6/K)
lake natural log of both sides (Ln)
-1.386 = -0.693 * 6 / K
K = 3 hr
Rumi123456789:
No is the initial amount of radioactive isotopes
N= Amount of radioactive isotope after time t
dont tell thank you because answer is 12 hrs
my answer is 3 hrs
May be ...... ask ur teacher regarding this question
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