Chemistry, asked by ashutosh784, 15 days ago

A Mencury Lamp is radiating monochnomatic
light of power
10 w The peak
value of electric
field strength at a distance of 5m from
The lamp is nearly.​

Answers

Answered by deepakojha11411
1

Answer:

, from equation 10, we can conclude that the amplitude of the electric field associated with the electromagnetic radiation at a distance of 5m from the lamp is nearly 2.68Vm−1. Hence, the correct answer is option B.

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