Question

A merchant bought 60 sheep at ₹120 per sheep.He sold 40 of them at ₹150. 10 of the sheep died. What should be the S.P. of the remaining sheep,if he wants a profit of ₹800?

Answer 1

Here is your solution

Given :-

Cost of each sheep = Rs 120 

Total number of sheep (x) = 60

So

Total Cost price = 120 × 60 = Rs 7200 .

Again

2/3 of total sheep(y) = 2/3 × 60 = 40

Selling price each of 2/3 of total sheep = 150

Total selling price of these sheep(y) = 150 × 40 = Rs6000 .

Again

10 sheep are death (z)

Total selling price of death sheep (z) = Rs 0

Number of remaining sheep => 60 - 40 - 10

=>10

Let Selling price of remaining sheep be s .

Profit = Selling price - Cost price

According to question

if we want a profit of Rs 800.

=>Total Selling price - 7200=800

Total Selling price = Rs8000 

Total Selling Price = y + z

8000 = 6000

HENCE

WE will subtract

S=Total sp -our consume sp.

S=8000 - 6000

s = 2000

Hence,

Selling price of 10 sheep is Rs 2000 .

Hope it helps

Answer 2

❤️_______Hey Mate ________❤️

✌️_______UR ANSWER_______✌️

cost of each sheep = 120 rupees

total number of sheep => X = 60

therefore total cost price = 120 x 60 = 7200 rupees..................................................

now 2/3 of sheep = so let suppose x1 =2/3x60=40................

selling price of each of 2/3 of total sheep = suppose y1 = 150

therefore total selling price of its sheep = 150 x 60 = 6000 ruppes

now 1/6 of total sheep = x3 = X - x1 - x2 = 60 - 40 - 10 => 10

let selling price of remaining sheep be suppose y3

profit = SP - CP

now... If we want a profit of 800 ruppes

800= total selling price - 7200

therefore total selling price = 8000 ruppes

total selling price = y1 +y2+y3

8000 = 6000 + 0 + y3
therefore y3 = 2000

now we selling price of 10 sheep = 2000 ruppes

therefore selling price of each sheep = 200 ruppes

therefore To make a profit of 800 Suman needs to sell remaining sheep at 200 ₹ each