Question

A merchant bought two transistor which together cost him rs 480.he sold one of them at a loss of 15% and other at a gain of 19%.if the selling ...

Answer 1

Let the two transistors be x and y. It is given

x+y=480 .....(1)

SP of x= ((100-15)/100)*x = 85x/100

SP 0f y=((100+119)/100)*y= 119y/100

Now, SP of both the transistors are equal. Therefore,

=>85x/100=119y/100

=> y= 85x/119

Put value of y in (1),

=> x+85x/119=480

=> x=280

From (1),

=>280+y=480

=>y=200

Therefore, cost of lowered price transistor is Rs. 200.

Answer 2

Answer:

200

Explanation:

cp of 1st transitor=x

cp of 2nd transior=480-x

as it given that sp of both transitor is equal therefore

85x/100=115(480-x)

after simplifying we get x as 280

there for price of lower transitor will be 480-280=200 answer

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