A merchant had a 40 kg measuring weight that broke into four pieces as the result of a fall. When the pieces were subsequently weighed, it was found that the weight of each piece was a whole number of kilograms and that the four pieces could be used to weigh every integral weight between 1 and 40 kg. What were the weight of the pieces.
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1 kg weight for aal 1to 40 broken piece
DiyaDebeshee:
how??
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Dear student,
Please find below the solution to the asked query:
We have to find weights of the 4 different pieces that can eb broken from a total wieght of 40 kg so that we can measure weight between 1 to 40.These four weights can be 1, 3, 9 and 27 kg.Then the weights from 1 to 40 can be measured as follows: 1 (given) 2=3−1 3 (given) 4=3+1 5=9−3−1 6=9−3 7=9−3−1 8=9−1 9 (given) 10=9+1 11=9+3−1 12=9+3 13=9+3+1 ⋮ ⋮ ⋮ 38=27+9+3−1 39=27+9+3 40=27+9+3+1Thus the required weights are, 1, 3, 9 and 27 kg
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Please find below the solution to the asked query:
We have to find weights of the 4 different pieces that can eb broken from a total wieght of 40 kg so that we can measure weight between 1 to 40.These four weights can be 1, 3, 9 and 27 kg.Then the weights from 1 to 40 can be measured as follows: 1 (given) 2=3−1 3 (given) 4=3+1 5=9−3−1 6=9−3 7=9−3−1 8=9−1 9 (given) 10=9+1 11=9+3−1 12=9+3 13=9+3+1 ⋮ ⋮ ⋮ 38=27+9+3−1 39=27+9+3 40=27+9+3+1Thus the required weights are, 1, 3, 9 and 27 kg
Hope this information will clear your doubts about the topic.
If you have any more doubts, just ask here on the forum and our experts will try to answer it as soon as
possible.
Regards
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