A merchant has 105 l of oil of one kind,175 l of another kind and 140 l of third kind.He wants to sell the oil by filling the three kinds of equal capacity.what should be greatest capacity of such a tin?
Answers
Answer:
Given 105 litres, 175 litres, 140 litres
HCF (105,175,140) = 60
So, the greatest capacity = 35:
Answer:
The greatest capacity of such tin is 35 liters
Step-by-step explanation:
Given: A merchant has three different oil.
- One kind of oil is 105 litres.
- Second kind of oil is 175 litres
- Third kind of oil is 140 litres
To find: The greatest capacity of tin
Solution:
The merchant has 3 different oils of 105 liters, 175 liters and 140 liters respectively.
He wants to sell the oil by filling the three kinds of equal capacity.
So the greatest capacity of the tin for filling three different types of oil is given by the H.C.F. of 105, 175 and 140
HCF:
- The H.C.F. defines the greatest factor existing between any given pair of two or more numbers.
- The term "H.C.F is also known as "the largest common factor"
To find the greatest capacity we have to use HCF factor.
First we will calculate H.C.F of 105 , 175 and 140 by Euclid’s division lemma.
HCF of 105 = 5×3 ×7
HCF of 140 = 2 × 7× 2 × 5
HCF of 175 = 5 × 5 × 7
Common factor in HCF = 5 × 7
= 35
Therefore the greatest capacity of tin = 35
Final answer:
The greatest capacity of such tin is 35 liters
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