Question

A merchant has 120 l of oil of one kind,180 l of another kind and 240 l of third kind.He wants to sell the oil by filling the three kinds of equal capacity.what should be greatest capacity of such a tin?

Answer 1

Given 120 litres, 180 litres, 240 litres

HCF (120,240,360)  = 60

So, the greatest capacity  = 60

Answer 2

We need to find the GCD-that is Greatest Common Divisor

gcd(120,180,240) = 60

So the merchant needs to fill 60 liters of all types of oils that is 3 times the gcd
=> 60*3 = 180 liters will used in filling all of the 3 equal tin containers.

The greatest capacity = 60 liters