Question

A merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?​

Answer 1

$\huge{\mathcal{\purple{A}\green{N}\pink{S}\blue{W}\purple{E}\green{R}\pink{!}}}$

We need to find the HCF or GCD that is Greatest Common Divisor.

120=23×3×5

180=22×32×5

240=24×3×5

Greatest Common Divisor=22×3×5=60

The greatest capacity = 60 liters

So, the merchant needs to fill 60 liters of all types of oils.

Answer 2

✨✨Answer is here✨✨

➡️✨✨see this pic✨✨

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