Question

A merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of a third kind. He wants to donate the oil by filling the three kinds of oil in tins of equal capacity in a religious place for making food for needy people . What should be the greatest capacity of such a tin ?

Answer 1

Step-by-step explanation:

Heya Rakesh friends

three kinds of oil in different quantities

120, 180, 240 litres

Now the oil is poured in tins of equal capacity ,

So the greatest capacity will be calculated by taking HCF of 120, 180 , 240

120 = 2 ×2 × 2 ×3 × 5

180 = 2 × 2 × 3×3 ×5

240 = 2 × 2 × 2 ×2 × 3 ×5

Common factor = 2 × 2 × 3 × 5 = 60.ans....

hope this will help you

Answer 2

Hi Samaira

How are you?

We need to find the HCF or GCD that is Greatest Common Divisor  

120= (2^3 ) ×3×5

180= (2^2)  ×(3 ^2 ) ×5

240=2 ^4  ×3×5

GCD=2  ^2  ×3×5=60

The greatest capacity = 60 liters

So the merchant needs to fill 60 liters of all types of oils  

Hence option C is correct