Math, asked by Anonymous, 8 months ago

A merchant has 120 litres of oil of one kind , 180 litres of another kind and 240 litres of third kind . he wants to sell the oil by filling the three kinds of oil in tins of equal capacity . what should be the greatest capacity of such a tin ??

Answers

Answered by arjun4671
1

Answer:

180 ltr

Step-by-step explanation:

120+180+240=540

x=540÷3

=180

180 litres

Answered by Anonymous
5

We need to find the HCF or GCD that is Greatest Common Divisor

120 = 2³×3×5

180=2²×3²×5

240=2⁴×3×5

GCD=2²×3×5=60

The greatest capacity = 60 liters

So the merchant needs to fill 60 liters of all types of oils

Hence option C is correct.

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