A merchant has 120 litres of oil of one kind , 180 litres of another kind and 240 litres of third kind . he wants to sell the oil by filling the three kinds of oil in tins of equal capacity . what should be the greatest capacity of such a tin ??
Answers
Answered by
1
Answer:
180 ltr
Step-by-step explanation:
120+180+240=540
x=540÷3
=180
180 litres
Answered by
5
We need to find the HCF or GCD that is Greatest Common Divisor
120 = 2³×3×5
180=2²×3²×5
240=2⁴×3×5
GCD=2²×3×5=60
The greatest capacity = 60 liters
So the merchant needs to fill 60 liters of all types of oils
Hence option C is correct.
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