A merchant has 132 litres of oil of one kind, 204 litres aui SITOurd we buy of another kind and 264 litres of third kind. the oil by filling the three kinds of oil in tins of equal capacity. What is the greatest capacity such a tin?
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Step-by-step explanation:
A merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?
We need to find the HCF or GCD that is Greatest Common Divisor
We need to find the HCF or GCD that is Greatest Common Divisor 120=2×2×2×3×5
We need to find the HCF or GCD that is Greatest Common Divisor 120=2×2×2×3×5180=2×2×3×3×5
We need to find the HCF or GCD that is Greatest Common Divisor 120=2×2×2×3×5180=2×2×3×3×5240=2×2×2×2×3×5
We need to find the HCF or GCD that is Greatest Common Divisor 120=2×2×2×3×5180=2×2×3×3×5240=2×2×2×2×3×5GCD=2×2×3×5=60
We need to find the HCF or GCD that is Greatest Common Divisor 120=2×2×2×3×5180=2×2×3×3×5240=2×2×2×2×3×5GCD=2×2×3×5=60The greatest capacity = 60 liters
We need to find the HCF or GCD that is Greatest Common Divisor 120=2×2×2×3×5180=2×2×3×3×5240=2×2×2×2×3×5GCD=2×2×3×5=60The greatest capacity = 60 litersSo the merchant needs to fill 60 liters of all types of oils