a merchant has 140 of oil of kind of one kind 500 of another kind and 330 of the third kind he want to sell this by packing and three kind of 3 equal capacitor when should be greatest capacity of a such a team
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Quantity of oil A = 120 liters Quantity of oil B = 180liters Quantity of oil C = 240liters We want to fill oils A, B and C in tins of the same capacity ∴ The greatest capacity of the tin chat can hold oil. A, B and C = HCF of 120, 180 and 240 By fundamental theorem of arithmetic
120 = 23 × 3 × 5 180 = 22 × 32 × 5 240 = 24 × 3 × 5
HCF = 22 × 3 × 5 = 4 × 3 × 5 = 60 litres
The greatest capacity of tin = 60
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